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2 years ago

I have to transfer this graph into a vertex form equation, but I'm not sure how to.

Mathematics

1 answer:

tino4ka555 [31]2 years ago

8 0

Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2

Step-by-step explanation:

vertex form is y=a(x-h)^2 + k

here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.

so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.

now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have

-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a

the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2

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Complete question

To find $\sqrt{5}$ , Beau found $2^2 = 4$ and $3^2 = 9$ . He said that since 5 is between 4 and 9, $\sqrt{5}$ , is between 2 and 3. Beau thinks a good estimate for $\sqrt{5}$ , is $\frac{2 + 3}{2} = 2.5$ Is his estimate high or low? How do you know?

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I have to transfer this graph into a vertex form equation, but I'm not sure how to.​

I have to transfer this graph into a vertex form equation, but I'm not sure how to.