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zubka84 [21]
2 years ago
5

If tan ⁡x=12/5, and 0°

Mathematics
1 answer:
Charra [1.4K]2 years ago
8 0

The value of sin(2x) is \frac{120}{169}

Explanation:

Given that tan x =\frac{12}{5}

The formula for sin(2x) is \sin (2 x)=2 \sin x \cos x

Since, \tan x=\frac{o p p}{a d j}

Also, it is given that tan x =\frac{12}{5}

Thus, opp=12 and adj=5

To find the hypotenuse, let us use the pythagoras theorem,

\begin{aligned}h y p &=\sqrt{12^{2}+5^{2}} \\&=\sqrt{144+25} \\&=\sqrt{169} \\&=13\end{aligned}

Now, we can find the value of sin x and cos x.

\sin x=\frac{\text { opp }}{h y p}=\frac{12}{13}

\cos x=\frac{a d j}{h y p}=\frac{5}{13}

Now, substituting these values in the formula for sin 2x, we get,

\begin{aligned}\sin (2 x) &=2 \sin x \cos x \\&=2\left(\frac{12}{13}\right)\left(\frac{5}{13}\right) \\&=\frac{120}{169}\end{aligned}

Thus, the value of sin(2x) is \frac{120}{169}

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