For the first one the answer is 17
34÷2=17
The total length was 6 m.
One of the tables was 1.8 m
Subtract 1.8 from 6 to find the total length of the other two tables:
6 - 1.8 = 4.2m
The other two tables are the same size, so now divide 4.2 m by 2:
4.2 / 2 = 2.1
The other tables are 2.1 m long.
4x^2 - 30 = 34
4x^2 = 34 + 30
4x^2 = 64
x^2 = 64/4
x^2 = 16
x = sqrt 16
x = -4 and 4......E and F
The answer is 642
Multiply<span> using long </span>multiplication<span>.</span>
Answer:
Given that The data to represent average test scores for a class of 16 students includes an outlier value of 78.
We can find sum of all 16 test scores = 84(16) = 1344
Outlier found = 78
If outlier is removed new sum = 1344-78 = 1266
Number of entries without outlier = 15
New average = 1266/12 =84.4
We find that average of new data increases.
Also whenever we remove outlier std deviation also would be reduced.
Step-by-step explanation: