I need help with 40 and 39!!!

Mathematics

2 answers:

Inessa [10]3 years ago

4 0

Answer:

39) Opt. A (24)

Step-by-step explanation:

39) 40 - 8(n) where n = 2

=> 40 - 8*2

=> 40 - 16

=> 24 Opt. A

And just for information, the answer you marked for 38th is wrong.

Formula = bh/2

b = 16

h = 12

bh/2 = 16*12/2

=192/2 = 96

Hope this helps u

Please mark as brainliest

Thank You

vagabundo [1.1K]3 years ago

3 0

39-A
When you multiply 8 times 2 its 16 and 40-16 is 24
40-D
less than is towards the negatives and for less than or greater than you use open circles

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A metallurgist has an alloy with 5

alexira [117]

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.30y\\
-----&-----&-------&-------\\
mixture&100&0.15&(100)(0.15)
\end{array}$

so hmm notice, we use the decimal format for the percent, namely 15% is just 15/100 and 5% is just 5/100 and so on

whatever the amounts of "x" and "y" are, they must add up to 100 grams
thus x + y = 100

and whatever the concentrated amounts are, they'll add up to (100)(0.15)

thus $\bf \begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.30y=(100)(0.15)\\
----------\\
0.05x+0.30\left( \boxed{100-x} \right)=(100)(0.15)
\end{cases}$

solve for "x", to see how much 5% alloy will be needed

what about "y"? well y = 100 -x

4 0

4 years ago

Some please help with this situation

maria [59]

answer:

$- a ^{3} b^{2} c^{2} - a^{2} b^{3} c ^{2} + a^{2} b^{2} c^{3}$