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Nutka1998 [239]
3 years ago
14

Lola pulls two marbles from a bag containing four red marbles, four blue marbles, and 12 yellow marbles without replacing them.w

hat is the probability that she pulled out a red marble first and a yellow marble second? express your answer in decimal form, rounded to the nearest hundredth.
Mathematics
2 answers:
Degger [83]3 years ago
5 0
It is the 2nd option. 0.13
Sauron [17]3 years ago
5 0

Answer:

The probability of that she pulled out a red marble first and a yellow marble second is:

0.13

Step-by-step explanation:

It is given that:

Lola pulls two marbles from a bag containing four red marbles, four blue marbles, and 12 yellow marbles without replacing them.

This means that there are a total of:4+4+12=20 marbles.

Now we are asked to find the probability that she pulled out a red marble first and a yellow marble second.

The probability of choosing a red marble out of 20 marbles is:

P_1=\dfrac{4}{20}

and the probability of choosing a yellow marble on the second draw(i.e. now we have to choose among the 19 remaining marbles) is:

Number of yellow marbles in the bag/19

=P_2=\dfrac{12}{19}

Hence, the probability of choosing a red and then a yellow marble is:

P=P_1\times P_2\\\\P=\dfrac{4}{20}\times \dfrac{12}{19}=\dfrac{12}{95}=0.1263157.

Hence, to the nearest hundredth the probability is:0.13

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ronaldo delivers the papers at the rate of 6 papers in 24 minutes. how much longer would it take him to deliver 56 papers than 4
UkoKoshka [18]

We are given

Ronaldo delivers the papers at the rate of 6 papers in 24 minutes

so, number of papers =6 in time =24 minutes

so, firstly we can find rate

rate = ( number of papers)/( time taken)

r=\frac{6}{24} =\frac{1}{4}

now, we can find times

Time for 56 papers:

we are given

number of papers =56

rate is

r=\frac{1}{4}

now, we can find time

t_1=\frac{56}{r}

t_1=\frac{56}{\frac{1}{4}}

t_1=224min

Time for 41 papers:

we are given

number of papers =41

rate is

r=\frac{1}{4}

now, we can find time

t_2=\frac{41}{r}

t_2=\frac{41}{\frac{1}{4}}

t_2=164min

now, we can find time difference

t=t_1-t_2

so, we can plug values

t=224-164

t=60 min..............Answer


8 0
4 years ago
Read 2 more answers
How do I work this out?
Maslowich
Here is the work and the answers. Hope this helps! Message for any conversations.

7 0
3 years ago
How many terms are in this expression? 5x y - 3x - 8 2
FromTheMoon [43]

The number terms in the given expression is 3, they are 5xy, -3x and -82.

The given expression is 5xy-3x-82.

<h3>What is an expression?</h3>

An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division.

The terms involved in an expression in math are:

Constant: A constant is a fixed numerical value.

Variable: A variable is a symbol that doesn't have a fixed value.

In the given expression 5xy-3x-82, there are three terms, which are 5xy, -3x and -82.

Therefore, the number terms in the given expression is 3, they are 5xy, -3x and -82.

To learn more about an expression visit;

brainly.com/question/28170201.

#SPJ1

7 0
2 years ago
A study found that out of 300 people 60% of them prefer to eat hamburgers rather than hot dogs. Find the 95% confidence interval
Lerok [7]

Answer:

(0.5446, 0.6554)

Step-by-step explanation:

As the sample is sufficiently large, the formula is used to estimate the proportion shown in the attached image.

Where:

P: sample proportion = 0.6

n: Sample size = 300

1-\alpha: Confidence level = 0.95

α: Significance = 0.05

Z_{\alpha / 2} = 1.96 *

* Obtained from the normal standard table.

When introducing these values in the formula shown in the image we obtain:

0.6 + 1.96 *\sqrt {\frac{0.6*0.4}{300}}

0.6 - 1.96 *\sqrt{\frac{0.6*0.4}{300}}

Finally, the confidence interval is:

(0.5446, 0.6554)

8 0
3 years ago
What is the simplified form of the rational expression below 6x^2-54 / 5x^2+15x
Vladimir [108]

Answer:

\large\boxed{\dfrac{6x^2-54}{5x^2+15x}=\dfrac{6(x-3)}{5x}=\dfrac{6x-18}{5x}}

Step-by-step explanation:

6x^2-54\qquad\text{distributive}\\\\=6(x^2-9)=6(x^2-3^2)\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=6(x-3)(x+3)\\\\5x^2+15x\qquad\text{distributive}\\\\=5x(x+3)\\-----------------\\\\\dfrac{6x^2-54}{5x^2+15x}=\dfrac{6(x-3)(x+3)}{5x(x+3)}\qquad\text{cancel}\ (x+3)\\\\=\dfrac{6(x-3)}{5x}=\dfrac{6x-18}{5x}

6 0
3 years ago
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