Because we know the area in terms of paint flow, and paint flow in terms of time, we can substitute p(t) for p in the A(p) equation.
A(p(t)) = A(t) = <span>π * (5t)^2 (assuming it's squared for the A(p).
B: 314 units^2
If A(p) = </span>πp2 (instead of p^2), then A(t) = 10πt
B: 31.4 units^2
I don’t know brotherrrr sprru
- <u>We </u><u>have </u><u>given </u><u>a</u><u> </u><u>right</u><u> </u><u>angled </u><u>triangle </u><u>whose </u><u>values </u><u>are </u><u>m</u><u>, </u><u> </u><u>n </u><u>and </u><u>2</u><u> </u>
- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>m </u><u>and </u><u>n</u>
<u>In </u><u>the </u><u>given </u><u>right </u><u>angled </u><u>triangle</u><u>, </u><u>we </u><u>have </u>
- Perpendicular height = n units
- Base = 2 units
- Hypotenuse = m units
<u>Now</u><u>, </u><u> </u><u>By </u><u>using </u><u>trigonometric </u><u>ratios </u>
<u>According </u><u>to </u><u>the </u><u>question </u><u>:</u><u>-</u>
- <u>We </u><u>know </u><u>that </u><u>,</u><u> </u><u>Sum </u><u>of </u><u>Angles</u><u> </u><u>of </u><u>triangle </u><u>is </u><u>1</u><u>8</u><u>0</u><u>°</u><u> </u><u>.</u>
<u>Therefore</u><u>, </u>
Let the unknown angle be x
<u>Now</u><u>, </u>
Thus, The value of m = 2√2 and n = 2