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ikadub [295]
3 years ago
9

1. A raffle prize of 14x^2/15 dollars is to be divided among 7x people. Write an expression for the amount of money that each pe

rson will receive.
(SHOW WORK)

2. For a short time after a wave is created by wind, the height of the wave can be modeled using y = a sin 2pi t/T , where a is the amplitude and T is the period of the wave in seconds.

How many times over the first 5 seconds does the graph predict the wave to be 2 feet high?
(SHOW WORK)
Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Step-by-step explanation:

Q1

7x people=14x^2/15

1 person= (14x^2/15)÷7x

// =(7x^2/15)÷x

Each person will recieve= (7x^2/15)÷x

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What is the value of the expression 0.52?
polet [3.4K]

Answer:

0.25

Step-by-step explanation:

lets say you have half a cake

multiplying a decimal is the same as multiplying its counterpart

basically, you divide half a cake in half

0.25 of a cake, or 1/4

uwu

6 0
3 years ago
Read 2 more answers
The degree of a polynomial is
scoundrel [369]
The degree of a polynomial is<span> the highest </span>degree<span> of its terms when the </span>polynomial is<span> expressed in its canonical form consisting of a linear combination of monomials.</span>The degree<span> of a term is the sum of the exponents of the variables that appear in it.</span>
5 0
3 years ago
What are the resulting coordinates of triangle A′B′C′ after reflecting triangle ABC across the origin if the vertices of triangl
Roman55 [17]

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C

Step-by-step explanation:

When reflecting across the origin, negetives become positives and positives become negetives.

Hope that helps!

6 0
3 years ago
Given that L is equidistant from M and K, find m<br> A. 23<br> B. 33<br><br> C. 55<br> D. 57
Anna11 [10]
The answer:
the full question is, <span>Given that L is equidistant from M and K, find m KLN
as we see on the figure
m</span>KLN ≈ mMLN, so 33 = 2y + 23
so 33 - 23 = 2y,   10° = 2y, and then y= 10/2 = 5° 

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6 0
4 years ago
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam. Find
Nonamiya [84]

The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N

<h3>How to find the Tension in Suspended Cables?</h3>

Resolving forces in the y direction gives us;

T₁ sin 29° + T₂ sin 53° = 210  ------(eq 1)

Resolving forces in the horizontal direction gives;

T₁ cos 29° = T₂ cos 53°   ----(eq 2)

T₁ = T₂ cos 53°/cos 29°

Thus;

(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210  

0.3336T₂ + 0.7986T₂ = 210

T₂ = 210/1.1322

T₂ = 185.48 N

Thus;

T₁ = 185.48 cos 53°/cos 29°

T₁ = 127.63 N

Read more about Tension in Cables at; brainly.com/question/11653585

#SPJ1

7 0
2 years ago
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