it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.
Let h(t) represent the height of the ball at time t.
Given that the height is given by:
h(t) = -16t² + 80t + 40
1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:
40 = -16t² + 80t + 40
16t² - 80t = 0
t(t - 5) = 0
t = 0 or t = 5
Hence it takes 5 seconds to reach a height of 40 ft.
2) The maximum height is at h'(t) = 0,
h'(t) = -32t + 80
-32t + 80 = 0
32t = 80
t = 2.5
It takes 2.5 seconds to reach maximum height.
Find out more at: brainly.com/question/11535666
Hey the answer is -0.2. You have to divide 10 by both sides to isolate the variable
Answer:
-1v
0.6y+2.1
3w-p+4
1-6x
0
-5x+10y+z-25
Step-by-step explanation:
Combine like terms
Answer:
1/2
Step-by-step explanation:
cot∅ = 1/tan∅
cot∅ = 1/2
Answer:
5
Step-by-step explanation:
