Answer:
Step-by-step explanation:
Suppose that the side length is s. Imagine that one side is level. Draw a vertical line through the top vertex perpendicular to the base (level side). Label this vertical line "h." Then h and s are related as follows:
√3 h
sin 60 degrees = ------- = --------
2 s
s√3
and so h = the height of the triangle = -----------
2
The area of this triangle is (1/2)(base)(height), which here is:
(1/2)(s/2)( s√3 /2), or
(s^2)√3
A = ---------------
8
2,4,44 because the gathing numbers are equal to represent
If you solve for theta, it would be 3pi/4
Answer:
4(5)+5y=20 20+5y=20 then subtract the 20 with other 20= 0
5y/5=0/5 y=0
Step-by-step explanation:
Answer:
Time = 3secs
Max height = 56m
Step-by-step explanation:
Given the height reached by the rocket modeled by the equation;
h(x) = -5(x - 3)² + 56 where;
x is in seconds
The rocket velocity at its maximum height is zero.
Hence dh/dx = 0
dh/dx = 2(-5)(x-3)
dh/dx = -10(x-3)
Since dh/dx = 0
0 = -10(x-3)
0 = -10x + 30
10x = 30
x = 3secs
<em>Hence it takes 3 secs to reach the maximum height.</em>
Get the maximum height reached by the rocket. Substitute x = 3 into the equation given;
Recall that:
h(x) = -5(x - 3)² + 56
If x = 3
h(3) = -5(3 - 3)² + 56
h(3) = 0 + 56
h(3) = 56
<em>Hence the maximum height that the rocket reaches is 56m</em>
