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4 years ago

9

Tracerouting is a process that can be used to gather information about a network during which of the seven phases of the informa

tion-gathering methodology?

Computers and Technology

2 answers:

svp [43]4 years ago

6 0

Answer:

The second phase which is : determining the network range.

Explanation:

The seven phases of information-gathering methodology are;

i. Gathering information

ii. Determining the range of the network

iii. Identifying the machines that are actively in use

iv. Locating access points and open ports

v. Performing operating system fingerprinting

vi. Performing fingerprinting services

vii. Network mapping.

In all of the phases, tracerouting takes place at the second phase which is determining the network range. Tracerouting, monitors, by tracing the route that a data packet follows from the server or host network to its destination.

Dahasolnce [82]4 years ago

5 0

Answer:

Locate the network range.

Explanation:

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3 years ago

In order to use NetWitness Investigator to analyze the same packets that you analyzed with Wireshark, you first had to save the

rusak2 [61]

Answer:

.pcap

Explanation:

He initially have to store the DemoCapturepcap.pcapng file throughout the older.pcap format in which of using NetWitness Examiner to examine a certain transmissions that the person examined with Wireshark.

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3 years ago

Why does an annular eclipse occur when the moon is between the sun and Earth, but is too far from Earth for a total eclipse?

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Answer:

Moon Is Far from Earth

Explanation:

The reason we can see the glowing outer edge of the Sun at the maximum point of an annular eclipse is that it happens while the Moon is near its farthest point from Earth, called apogee, when the Moon is smaller than the Sun when viewed from Earth.

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3 years ago

Note: You can use a word document to write your answers and copy-paste your answer to the area specified. a. (5 points) Convert

MrMuchimi

Answer:

$EA9_{16} = 3753$

$CB2_{16} = 3250$

$(1011 1110 1101 1011 1010)_2 = 781754$

$(1010 1000 1011 1000 1110 1101)_2 = 11057389$

$(1011 1110 1101 1011 1010)_2 = BEDBA$

$(1010 1000 1011 1000 1110 1101)_2 = A8B8ED$

$74510_8= 221416$

$67210_8 = 203212$

Explanation:

Solving (a): To base 10

$(i)\ EA9_{16$

We simply multiply each digit by a base of 16 to the power of their position.

i.e.

$EA9_{16} = E * 16^2 + A * 16^1 + 9 * 16^0$

$EA9_{16} = E * 256 + A * 16 + 9 * 1$

In hexadecimal

$A = 10; E = 14$

So:

$EA9_{16} = 14 * 256 + 10 * 16 + 9 * 1$

$EA9_{16} = 3753$

$(ii)\ CB2_{16}$

This gives:

$CB2_{16} = C * 16^2 + B * 16^1 + 2 * 16^0$

$CB2_{16} = C * 256 + B * 16 + 2 * 1$

In hexadecimal

$C = 12; B =11$

So:

$CB2_{16} = 12 * 256 + 11 * 16 + 2 * 1$

$CB2_{16} = 3250$

Solving (b): To base 10

$(i)\ (1011 1110 1101 1011 1010)_2$

We simply multiply each digit by a base of 2 to the power of their position.

i.e.

$(1011 1110 1101 1011 1010)_2 = 1 * 2^{19} + 0 * 2^{18} + 1 * 2^{17} + 1 * 2^{16} +1 * 2^{15} + 1 * 2^{14} + 1 * 2^{13} + 0 * 2^{12} + 1 * 2^{11} + 1 * 2^{10} + 0 * 2^9 + 1 * 2^8 +1 * 2^7 + 0 * 2^6 + 1 * 2^5 + 1 * 2^4 + 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 0 * 2^0$

$(1011 1110 1101 1011 1010)_2 = 781754$

$(ii)\ (1010 1000 1011 1000 1110 1101)_2$

$(1010 1000 1011 1000 1110 1101)_2 = 1 * 2^{23} + 0 * 2^{22} + 1 * 2^{21} + 0 * 2^{20} +1 * 2^{19} + 0 * 2^{18} + 0 * 2^{17} + 0 * 2^{16} + 1 * 2^{15} + 0 * 2^{14} + 1 * 2^{13} + 1 * 2^{12} +1 * 2^{11} + 0 * 2^{10} + 0 * 2^9 + 0 * 2^8 + 1 * 2^7 + 1 * 2^6 + 1 * 2^5 + 0 * 2^4 + 1*2^3 + 1 * 2^2 + 0 * 2^1 + 1 * 2^0$

$(1010 1000 1011 1000 1110 1101)_2 = 11057389$

Solving (c): To base 16

$i.\ (1011 1110 1101 1011 1010)_2$

First, convert to base 10

In (b)

$(1011 1110 1101 1011 1010)_2 = 781754$

Next, is to divide 781754 by 16 and keep track of the remainder

$781754/16\ |\ 48859\ R\ 10$

$48859/16\ |\ 3053\ R\ 11$

$3053/16\ |\ 190\ R\ 13$

$190/16\ |\ 11\ R\ 14$

$11/16\ |\ 0\ R\ 11$

Write out the remainder from bottom to top

$(11)(14)(13)(11)(10)$

In hexadecimal

$A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.$

$(11)(14)(13)(11)(10)=BEDBA$

So:

$(1011 1110 1101 1011 1010)_2 = BEDBA$

$ii.\ (1010 1000 1011 1000 1110 1101)_2$

In b

$(1010 1000 1011 1000 1110 1101)_2 = 11057389$

Next, is to divide 11057389 by 16 and keep track of the remainder

$11057389/16\ |\ 691086\ R\ 13$

$691086/16\ |\ 43192\ R\ 14$

$43192/16\ |\ 2699\ R\ 8$

$2699/16\ |\ 168\ R\ 11$

$168/16\ |\ 10\ R\ 8$

$10/16\ |\ 0\ R\ 10$

Write out the remainder from bottom to top

$(10)8(11)8(14)(13)$

In hexadecimal

$A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.$

$(10)8(11)8(14)(13) = A8B8ED$

So:

$(1010 1000 1011 1000 1110 1101)_2 = A8B8ED$

Solving (d): To octal

$(i.)\ 74510$

Divide 74510 by 8 and keep track of the remainder

$74510/8\ |\ 9313\ R\ 6$

$9313/8\ |\ 1164\ R\ 1$

$1164/8\ |\ 145\ R\ 4$

$145/8\ |\ 18\ R\ 1$

$18/8\ |\ 2\ R\ 2$

$2/8\ |\ 0\ R\ 2$

Write out the remainder from bottom to top

$74510_8= 221416$

$(ii.)\ 67210$

Divide 67210 by 8 and keep track of the remainder

$67210/8\ |\ 8401\ R\ 2$

$8401/8\ |\ 1050\ R\ 1$

$1050/8\ |\ 131\ R\ 2$

$131/8\ |\ 16\ R\ 3$

$16/8\ |\ 2\ R\ 0$

$2/8\ |\ 0\ R\ 2$

Write out the remainder from bottom to top

$67210_8 = 203212$

8 0

3 years ago

Use the get_seconds function to work out the amount of seconds in 2 hours and 30 minutes, then add this number to the amount of

Andrej [43]

Answer:

Since the get_seconds function is not given, I'll implement it myself;

The full program (get_seconds and main) written in python is as follows:

def get_seconds(hour,minute,seconds):

seconds = hour * 3600 + minute * 60 + seconds

return seconds

time1 = get_seconds(2,30,0)

time2 = get_seconds(0,45,15)

result = time1 + time2

print(result)

Explanation:

<em>The get_seconds defines hour, minute and seconds as its arguments</em>

This line defines the get_seconds function

def get_seconds(hour,minute,seconds):

This line calculates the second equivalent of the time passed to the function

seconds = hour * 3600 + minute * 60 + seconds

This line returns the the calculated seconds equivalent of time

return seconds

The main starts here

This line calculates the number of seconds in 2 hours and 30 minutes

time1 = get_seconds(2,30,0)

This line calculates the number of seconds in 45 minutes and 15 seconds

time2 = get_seconds(0,45,15)

This line adds both together

result = time1 + time2

This line prints the result

print(result)

5 0

4 years ago