Answer:
Latency of an object O is shown below.
Explanation:
W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R
latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]
After combining the two case
latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]
where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.
server time for transmit the object is (K-1)[S/R +RTT - WS/R]
Answer:
0.001625
Explanation:
if the velocity of an object is lower than 1% of light speed
1-Input unit
2-output unit
3-storage
4-central processing unit
5-arithmetic and logic unit
<span>It should be single-user/multitasking os.</span>
Answer: Computer memory is of two basic type – Primary memory(RAM and ROM) and Secondary memory(hard drive,CD,etc.). Random Access Memory (RAM) is primary-volatile memory and Read Only Memory (ROM) is primary-non-volatile memory.
Explanation: Hope this helps :)
