Start by decomposing the number inside the root into primes
Then group the terms into cubes if possible
rewrite the root
![\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D%5Csqrt%5B3%5D%7B10%5Ccdot2%5E3%7D)
then cancel the terms that are cubes and bring them out of the root
![\sqrt[3]{80}=2\sqrt[3]{10}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D2%5Csqrt%5B3%5D%7B10%7D)
Answer:
86362600
Step-by-step explanation:
We want to round to the hundreds place
We look at the 7 in the tens place. Since it is 5 or greater we round up
86,362,575 round to 86362600
This can help you
a) since it is discrete we need to think about the sum thing
it it was continuous we would look at an integral thing
so I think if I remember correctly we need to find c such that
<span><span>∑<span>i=0</span>3</span>c(<span>x2</span>+4)=1
b) </span>
problem b is a similar setup
Answer:
3/4
Step-by-step explanation:
The amplitude always comes before the operation(cos, tan...)
Answer:
Range=65
Step-by-step explanation:
The highest is 66 the lowest is 1 so 66-1=65
