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mr Goodwill [35]
3 years ago
11

Simplify. A) 4√3 + 6 B) 6√3 + 4 C) 6√6 + 3

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0
\frac{ 8\sqrt{6mn} + 6\sqrt{8mn} }{ 2\sqrt{2mn}}

First, break it up into two fractions:

\frac{ 8\sqrt{6mn} + 6\sqrt{8mn} }{ 2\sqrt{2mn}} = \frac{8\sqrt{6mn}}{ 2\sqrt{2mn}} + \frac{6\sqrt{8mn}}{ 2\sqrt{2mn}}

Next, you can simplify the numbers outside of the square root:

\frac{8\sqrt{6mn}}{ 2\sqrt{2mn}} + \frac{6\sqrt{8mn}}{ 2\sqrt{2mn}} = \frac{4\sqrt{6mn}}{\sqrt{2mn}} + \frac{3\sqrt{8mn}}{\sqrt{2mn}}

Since the values are being acted by the same function, being under a radical, you can simplify these too:

\frac{4\sqrt{6mn}}{\sqrt{2mn}} + \frac{3\sqrt{8mn}}{\sqrt{2mn}} = {4\sqrt{3}} + {3\sqrt{4}}

Finally, the square root of 4 is 2, so it would be expressed like this:

{4\sqrt{3}} + {3\sqrt{4}} = {4\sqrt{3}} + {3(2) = {4\sqrt{3}} + 6

Your answer should be A.
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2 years ago
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Suppose a van gets 22 mi/gal. The distance traveled D(g) is a function of the gallons of gas used
babymother [125]

Answer:

a) Table and graph showed

b) The distance will be 231 miles

c) Yes

Step-by-step explanation:

We know the van gets 22 mi/gal, so the distance D in miles traveled by the van can be expressed as  

D(g)=22g, being g the number of gallons of gas used

a) The graph of the function D and its corresponding table of values is shown below.  

b) If the van used g=10.5 gallons of gas, the distance would be:

D(10.5)=22 x 10.5 = 231 miles

c) The values of g are real in nature because they represent the amount of gas consumed by the van and it can be any real positive number. Being D a linear function of g, it also happens to take positive real values. Then it makes sense to connect the points with lines.

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3 years ago
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garik1379 [7]

Answer:

No mabey c

Step-by-step explanation:

6 0
3 years ago
HELP 283829 MATH!!!!!!!!!!!!!!
STatiana [176]
For the first one, you're answer would be AC. since C is also a right angle, and angle A is hypnotenuse to C
3 0
3 years ago
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Algebra problem help
True [87]
To solve this problem you must apply the proccedure below:

 1. You have that one canned juice drink is 20% orange juice and another is 5% orange juice.

 2. You must make a system of equation, as below:

 x+y=15  (i)
 0.20x+0.05y=0.15x15   (ii)

 3. Now, you must find the value of x (the liters of the first canned needed) and y (the liters of the other canned needed):

 x+y=15  (i)
 x=15-y

 0.20x+0.05y=0.15x15   (ii)
 0.20(15-y)+0.05y=2.25
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 x+y=15  (i)
 x=15-5
 x=10 liters

 4. Therefore, the asnwer is:

 10 liters of the canned juice drink that is 20% orange juice and 5 liters of the other canned juice drink that is 5% orange juice.

 
4 0
3 years ago
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