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stiks02 [169]
3 years ago
11

Using the scenario below, answer the following questions:

Computers and Technology
1 answer:
4vir4ik [10]3 years ago
3 0

Answer:

Here is code in java.

import java.util.*;

class Main

{

public static void main (String[] args) throws java.lang.Exception

{

   try{

         boolean flag=false;

         int total_mile=0;

         double avg_mile;

       // part 1, create and initialize array

       int inp[]={2,5,9,11,13,17,20,22,24,26};

       

       System.out.print("miles ran per week: ");

       // print the miles per week of train

       for(int x=0;x<10;x++)

       {

       System.out.print(inp[x]+" ");

       }

        System.out.println();

       //part 2, print the value of index 2 in the list

       System.out.println("value at index 2: "+inp[2]+" miles");

       //part 3, find length of array

       System.out.println("list length: "+inp.length);

     

       // part 4, calculate total mile and average

       for(int y=0;y<10;y++)

       {

       total_mile=total_mile+inp[y];

       }

       System.out.println("total miles ran: "+total_mile+" miles");

       

       avg_mile=total_mile/10.0;

       System.out.println("average no of miles ran= "+avg_mile+" miles");

       

     // part 5, check 4 exist in the list or not

       for(int k=0;k<10;k++)

       {

       if(inp[k]==4)

       {

       flag=true;

       break;

           }

       }

           if(flag)

           System.out.println("4 exist in the list.");

           else

            System.out.println("4 doesn't exists in the list.");  

       

   }catch(Exception ex){

       return;}

}

}

Explanation:

Create and initialize array with list value equals to 2 and maximum value 26. Print the miles of each week.Then find the value of miles at index 2 in the list.Next find the length of the array and print it.Calculate total miles ran of 10 weeks.Then calculate the average miles by dividing the total with 10. In the array, check 4 exist or not.

Output:

miles ran per week: 2 5 9 11 13 17 20 22 24 26                                                                            

value at index 2: 9 miles                                                                                                  

list length: 10                                                                                                            

total miles ran: 149 miles                                                                                                

average no of miles ran= 14.9 miles                                                                                        

4 doesn't exists

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Sketch f(x) = 5x2 - 20 labelling any intercepts.​
Norma-Jean [14]

Answer:

  • The graph of the function is attached below.
  • The x-intercepts will be: (2, 0), (-2, 0)
  • The y-intercept will be: (-20, 0)

Explanation:

Given the function

f\left(x\right)\:=\:5x^2-\:20

As we know that the x-intercept(s) can be obtained by setting the value y=0

so

y=\:5x^2-\:20

switching sides

5x^2-20=0

Add 20 to both sides

5x^2-20+20=0+20

5x^2=20

Dividing both sides by 5

\frac{5x^2}{5}=\frac{20}{5}

x^2=4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

so the x-intercepts will be: (2, 0), (-2, 0)

we also know that the y-intercept(s) can obtained by setting the value x=0

so

y=\:5(0)^2-\:20

y=0-20

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From the attached figure, all the intercepts are labeled.

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