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kakasveta [241]
3 years ago
15

3.26 LAB: Leap Year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate a

round the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year.
Computers and Technology
2 answers:
Taya2010 [7]3 years ago
6 0

Answer:

// program in C++ to check leap year.

// include header

#include<iostream>

using namespace std;

// main function

int main() {

// variable

  int inp_year ;

  // ask user to enter year

  cout<<"Enter year:";

  // read year

  cin>>inp_year;

  // check year is leap or not

  if (((inp_year % 4 == 0) && (inp_year % 100 != 0)) || (inp_year % 400 == 0))

  // if leap year , print leap year

     cout<<inp_year<<" is a leap year.";

  else

  // print not leap year

     cout<<inp_year<<" is not a leap year.";

  return 0;

}

Explanation:

Read year from user.Then check if year is divisible by 4 and not divisible by 100 or year is divisible by 400 then year is leap year.otherwise year is not  leap year.

Output:

Enter year:1712                                                                                                            

1712 is a leap year.

Lera25 [3.4K]3 years ago
5 0

Answer:

#include <iostream>

using namespace std;

int main() {

  int inputYear;

 cin>>inputYear;

 // check year is leap or not

 if (((inputYear % 4 == 0) && (inputYear % 100 != 0)) || (inputYear % 400 == 0))

 // if leap year , print leap year

    cout<<inputYear<<" - leap year" << endl;

 else

 // print not leap year

    cout<<inputYear<<" - not a leap year" << endl;

 

  /* Type your code here. */

  return 0;

}

Explanation:

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Explanation:

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Answer:

The program to this question can be given as:

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#include <stdio.h> //include header file.

int main() //defining main method

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Output:

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Explanation:

  • In the above C language program, firstly a header file is included. Then the main method is defined in this, a method contains a char variable that is "i and j". This variable is used in for loop, that is used to print the pattern.
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Answer:

import random

computer = random.randint(0, 2)

user = int(input("scissor (0), rock (1), paper (2): "))

if computer == 0:

   if user == 0:

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   elif user == 1:

       print("The computer is scissor. You are rock. You won")

   elif user == 2:

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elif computer == 1:

   if user == 0:

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   elif user == 1:

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   elif user == 2:

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elif computer == 2:

   if user == 0:

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Explanation:

*The code is in Python.

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Generate a random number between 0 and 2 (inclusive) using randint() method and set it to the computer variable

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If it is 0, check the value of user variable. If user is 0, it is a draw. If user is 1, user wins. If user is 2, computer wins

If it is 1, check the value of user variable. If user is 0, computer wins. If user is 1, it is a draw. If user is 2, user wins

If it is 2, check the value of user variable. If user is 0, user wins. If user is 1, computer wins. If user is 2, it is a draw

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