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kakasveta [241]
3 years ago
15

3.26 LAB: Leap Year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate a

round the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year.
Computers and Technology
2 answers:
Taya2010 [7]3 years ago
6 0

Answer:

// program in C++ to check leap year.

// include header

#include<iostream>

using namespace std;

// main function

int main() {

// variable

  int inp_year ;

  // ask user to enter year

  cout<<"Enter year:";

  // read year

  cin>>inp_year;

  // check year is leap or not

  if (((inp_year % 4 == 0) && (inp_year % 100 != 0)) || (inp_year % 400 == 0))

  // if leap year , print leap year

     cout<<inp_year<<" is a leap year.";

  else

  // print not leap year

     cout<<inp_year<<" is not a leap year.";

  return 0;

}

Explanation:

Read year from user.Then check if year is divisible by 4 and not divisible by 100 or year is divisible by 400 then year is leap year.otherwise year is not  leap year.

Output:

Enter year:1712                                                                                                            

1712 is a leap year.

Lera25 [3.4K]3 years ago
5 0

Answer:

#include <iostream>

using namespace std;

int main() {

  int inputYear;

 cin>>inputYear;

 // check year is leap or not

 if (((inputYear % 4 == 0) && (inputYear % 100 != 0)) || (inputYear % 400 == 0))

 // if leap year , print leap year

    cout<<inputYear<<" - leap year" << endl;

 else

 // print not leap year

    cout<<inputYear<<" - not a leap year" << endl;

 

  /* Type your code here. */

  return 0;

}

Explanation:

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