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vivado [14]
3 years ago
11

X^- x - 6 and x^ -5x +6 what are thier common factors

Mathematics
1 answer:
Katarina [22]3 years ago
6 0

I guess you mean:

X^2 - X - 6   and X^2 - 5X + 6

X^2 - X - 6 = (X + 2)(X − 3)

X^2 - 5X + 6 = (X − 2)(X − 3)

Based on that, their common factor is:

(X - 3)

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40 - 10 + 20
marin [14]

Answer:

The answer is 50

Step-by-step explanation:

40-10=30

30+20=50

4 0
2 years ago
Determining Prime factorization of 20
Elden [556K]
The number 20 is not a prime number.
5 0
3 years ago
Read 2 more answers
Which ordered pair is a solution to this equation?
ElenaW [278]
For (11, 1): (11 + 3)1 = 14(1) = 14
For (5, 2): (5 + 3)2 = 8(2) = 16 ≠ 14
For (7, 2): (7 + 3)2 = 10(2) = 20 ≠ 14
For (3, 2): (3 + 3)2 = 6(2) = 12 ≠ 14

Therefore, (11, 1) is a solution to this equation.
8 0
3 years ago
Write and then solve the differential equation for the statement: "The rate of change of y with respect to x is inversely propor
sesenic [268]
Brief review of proportionality relationships:

When two quantities a,b are \textbf{directly} proportional, that means any change in a manifests a \textbf{direct} change (think "in the same direction") in b.

Silly example: "The more I eat, the fatter I get." Here the amount one eats is directly proportional to one's body weight.

This change isn't always one-for-one, so we introduce a constant k to account for any scaling that occurs on either variables behalf. In general, though, we can write a directly proportional relationship as a=kb.

Now, when a,b are \textbf{inversely} proportional, then a change in a manifests a change in b in the \textbf{inverse} (opposite) direction.

Silly example: "The more I eat, the less thin I get."

This time we write the relation as ab=k.

To get back to your problem: To say that the rate of change of y(x) is inversely proportional to \sqrt y is to say that there is some constant k such that

\sqrt y\dfrac{\mathrm dy}{\mathrm dx}=k

This is a separable ODE:

y^{1/2}\,\mathrm dy=k\,\mathrm dx
\displaystyle\int y^{1/2}\,\mathrm dy=\int k\,\mathrm dx
\dfrac23y^{3/2}+C_y=kx+C_x
\dfrac23y^{3/2}=kx+C
y^{3/2}=\dfrac{3k}2x+C
y=\left(\dfrac{3k}2x+C\right)^{2/3}
8 0
3 years ago
John and will ran for 6th grade class president. There were
Luden [163]

Answer:

John had 12 more votes than Will.

Step-by-step explanation:

36 students = 36 votes

John = 2*Will

Will = 1 vote

36/3 = 12

  • 1 vote = Will
  • 2 vote = Johm
  • 2 vote = Will
  • 4 vote = John
  • 3 vote = Will
  • 6 vote = John
  • 6 vote = Will
  • 12 vote = John
  • 18 vote = Will
  • 36 vote = John
  • 12 vote = Will
  • 24 vote = John
7 0
3 years ago
Read 2 more answers
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