Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
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We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
Step-by-step explanation:
since we are required to find side |BC| and the value of side |AB| is given as 6.3 cm
hence we find the cosine of the given angle...
cos71 = adjacent ÷ hypotenuse
cos71 = |AB| ÷ |BC|
cos 71 = 6.3 ÷ |BC|
|BC| = 6.3 ÷ 0.325
|BC| = 19.4 cm
She cover more distance after rest 101.7-88.4625=13.2375