Step-by-step explanation:
Any complex number is of the form: 
where a is real part and B is imaginary part.
Therefore, in given complex number: 
7 is real part.
is imaginary part.
Hence, first two options are correct.
Last two options are incorrect because of the following reasons:
is coefficient of 
& not 
Given number is a difference of a real number and imaginary number & not a sum of a real number and imaginary number.
We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.
9514 1404 393
Answer:
Step-by-step explanation:
Using the transformation ...
(x,y) ⇒ (y, -x) . . . . . . rotation 90° CW
we have ...
A(-4, 4) ⇒ A'(4, 4)
B(-2, 4) ⇒ B'(4, 2)
C( -2, 1) ⇒ C'(1, 2)
Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
