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Veseljchak [2.6K]
3 years ago
9

What are 2 points on the graph for 6x-5y=25

Mathematics
1 answer:
zepelin [54]3 years ago
8 0
To find any two random point on the graph of 6x-5y=25, we can just plug in any two values for x and solve for y, and find the 2 points in the form of (x,y).

So lets plug in x=0.

\sf 6x-5y=25
\sf 6(0)-5y=25
\sf -5y=25
\sf y=-5
So one point is (0,-5)

And to find another point, we can plug in x=1

\sf 6x-5y=25
\sf 6(1)-5y=25
\sf 6-5y=25
\sf -5y=25-6
\sf -5y=19
\sf y=19/-5
\sf y=-3.8
So another point is (1,-3.8)
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Mike pays $20 per hour for algebra tutoring. The equation y = 20x relates the cost of tutoring (y) to the number of hours (x) he
kotykmax [81]

The unit rate in the equation is 20.

Option C) is the correct answer.

<u>Step-by-step explanation</u>:

Step 1 :

In the given equation y = 20x

where,

x ⇒ total number of hours for tutoring

20 ⇒  the cost per hour of tutoring

y ⇒ the total cost for total hours of tutoring

Step 2 :

Unit rate refers to the value per hour.

Here, the cost for 1 hour of tutoring is $20.

∴ The unit rate is $20 per hour of tutoring.

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3 years ago
The degree of a polynomial is
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What are the factors of 4 and 10?
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Read 2 more answers
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Stella [2.4K]

Answer:

i forgo

Step-by-step explanation:

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2 years ago
g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected
Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

np=50*0.78=39  \geq 10

n(1-p)=50*(1-0.78)=11 \geq 10

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}})

With the following parameters:

\mu_ p = 0.78

\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

np=50*0.78=39  \geq 10

n(1-p)=50*(1-0.78)=11 \geq 10

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}})

With the following parameters:

\mu_ p = 0.78

\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586

6 0
3 years ago
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