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Allisa [31]
3 years ago
5

If two triangles have equal perimeters, then they could also have which of the following? Select all that apply.

Mathematics
1 answer:
Radda [10]3 years ago
4 0

Answer: The answers is (B) equal areas.

Step-by-step explanation:  Given that two triangles have equal perimeters.

As shown in the attached figure, let us consider two right-angles triangles, ΔABC and ΔDEF, with sides AB = 3 cm, BC = 4 cm, AC = 5 cm, DE = 4 cm, EF = 3 cm and DF = 5 cm.

So the perimeters of both the triangles = 3 + 4 + 5 = 4 + 3 + 5 = 12 cm.

Since volume term is not valid in case of triangles, so they cannot have equal volumes. Therefore, option (A) is incorrect.

Area of ΔABC is

A_{ABC}=\dfrac{1}{2}\times AB \times BC = \dfrac{1}{2}\times 3\times 4=6~\textup{cm}^2,

and area of ΔDEF is

A_{DEF}=\dfrac{1}{2}\times DE\times EF=\dfrac{1}{2}\times 4\times 3=6~\textup{cm}^2.

Therefore, they may have equal areas and so option (B) is correct.

If the triangles have equal bases, then the heights will also be equal and both the triangles will be same. Similar is the case with equal heights. So, options (C) and (D) are incorrect.

Thus, the correct option is (B). equal areas.

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The rectangle below represents the base of a rectangular prism. If the
Andrews [41]

Answer:

64

Step-by-step explanation:

hiiii

to find volume the formula is

base * width * height.

so all we would have to do here is:

5 1/3 * 2 * 6=64.

hope this helped you :)

4 0
3 years ago
The square root of 9x plus 7 plus the square rot of 2x equall to 7
Oliga [24]
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x=2
4 0
3 years ago
PLEASE HELP
max2010maxim [7]

Hello!


So, this is quite the complex question, and here are the following steps:


What is the quotient of \frac{6-3\sqrt[3]{6}}{\sqrt[3]{9}}?

\frac{(6 - 3\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (rationalize the denominator)

\frac{3(2 -\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (factor 3 from the expression)

\frac{(2-\sqrt[3]{6})\sqrt[3]{9^{2}}}{3} (reduce the fraction with 3)

\frac{2\sqrt[3]{9^{2}}-\sqrt[3]{9^{2}}}{3} (distributive property)

\frac{2\sqrt[3]{81}-\sqrt[3]{486}}{3} (simplify 3 · 9²)

\frac{6\sqrt[3]{3}-3\sqrt[3]{18}}{3} (simplify the radical)

\frac{3(2\sqrt[3]{3}-3\sqrt[3]{18})}{3} (factor 3 from the expression)

2\sqrt[3]{3}-\sqrt[3]{18} (reduce the fraction)


The answer, is simply, choice A, 2\sqrt[3]{3} -\sqrt[3]{18} ≈ 0.263758.

5 0
3 years ago
Four times a number is the same as the difference of three times a number and four find the number round your answer to the near
maksim [4K]

Answer:

4

Step-by-step explanation:

Its four because:

4 x 3 = 12

12 + 4 = 16

4 x 4 = 16

Four times times three plus four is like saying four times four.

4 0
3 years ago
Read 2 more answers
Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree
kompoz [17]

Answer:

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zero 1 with multiplicity 3.

So

p(x) = (x-1)^3

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

p(x) = (x-1)^3(x-4)^2

Zero -3 with multiplicity 1:

Considering the previous zeros:

p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

8 0
2 years ago
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