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3 years ago

Determine the domain

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

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I don't know how to do this

Phantasy [73]

I completely agree with the above statement

3 0

3 years ago

A bag contains only red and blue marbles. Yasmine takes one marble at random from the bag. The probability that she takes a red

mamaluj [8]

Let red marbles = X.

The probability is 1 out of 5, written as 1/5

1/5 in terms of red marbles is equal to the number of red marbles divided by 5x, where 5x is the total number of marbles.

1/5 = x/5x

Now you have 5x total marbles, x red and 4x blue.

Add 5 more red and the new probability is:

(x+5)/(5x+5) = 1/3

Simplify:

3x+15 = 5x+5

Now solve for x:

Subtract 3x from both sides:

15 = 2x +5

Subtract 5 from each side:

2x = 10

Divide both sides by 2:

x = 10/2

X = 5

There were originally 5 red marbles.

5 0

3 years ago

Can someone please help with this math question:)

Bingel [31]

Solution:

The rationalisation factor for $\frac{1}{ a - \sqrt{b} }$ is $a + \sqrt{b}$

So, let us apply it here.

$\frac{1}{5 - \sqrt{2} }$

The rationalising factor for 5 - √2 is 5 + √2.

Therefore, multiplying and dividing by 5 + √2, we have

$= \frac{1}{5 - \sqrt{2} } \times \frac{5 + \sqrt{2} }{5 + \sqrt{2} } \\ = \frac{5 + \sqrt{2} }{(5 - \sqrt{2})(5 + \sqrt{2} ) } \\ = \frac{5 + \sqrt{2} }{ {(5)}^{2} - ( \sqrt{2})^{2} } \\ = \frac{5 + \sqrt{2} }{25 - 2} \\ = \frac{5 + \sqrt{2} }{23}$

Answer:

$\frac{5 + \sqrt{2} }{23}$

Hope you could understand.

If you have any query, feel free to ask.

5 0

2 years ago

Read 2 more answers

The length of AC⎯⎯⎯⎯⎯ is 10 inches.

Maru [420]

Answer:

5 in

Step-by-step explanation:

AC = the diameter

FA = the radius

diameter=2*radius

10=2*FA

FA=10/2

FA=5 in

3 0

3 years ago

Read 2 more answers

How many 6 digit different locker combinations are possible if no repeat numbers are allowed?

Alex_Xolod [135]

Since we are trying to find the number of sequences can be made without repetition, we are going to use a combination.

The formula for combinations is:

$_n C _k = \dfrac{n!}{k! (n - k)!}$

$n$ is the total number of elements in the set
$k$ is the number of those elements you are desiring

Since there are 10 total digits, $n = 10$ in this scenario. Since we are choosing 6 digits of the 10 for our sequence, $k = 6$ in this scenario. Thus, we are trying to find $_{10} C _6$ . This can be found as shown:

$_{10} C _6 = \dfrac{10!}{6! \cdot 4!} = \dfrac{10 \cdot 9 \cdot 8 \cdot 7}{4!} = \dfrac{5040}{24} = 210$

There are 210 total combinations.

7 0

3 years ago