Write an equation of the line using function notation. Horizontal; through (0,-2)

Mathematics

1 answer:

Mnenie [13.5K]2 years ago

7 0

Horizontal means the equation is y=something

(x,y)
(0,-2)
y=-2 is the equaiton
or
f(x)=-2

You might be interested in

Julia was creating similar triangles in the coordinate plane. The first triangle had a rise of 3 and a run of 10. The second tri

valina [46]

Yes julia is correct the run of the scond similar triangle will be b2=25.

<h3>What are simlilar traingles?</h3>

The similar triangle are those whose three sides or one angle or two sides or two angles one side are equal.

In the given:

Height of first triangle h=3

Base of first traingle =10

Height of second triangle =7.5

The base of second triangle b2 = ?

From the triangle similarity

$\dfrac{h_1}{b_1}=\dfrac{h_2}{b_2}$

$\dfrac{3}{10}=\dfrac{7.5}{b_2}$

$b_2=\dfrac{7.5\times 10}{3}$

$b_2=25$

Thus julia is correct the run of the scond similar triangle will be b2=25.

To know more about similar triangle follow

brainly.com/question/2644832

3 0

2 years ago

In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively.

Irina-Kira [14]

Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.

$c^{2} = a^{2} + b^{2} - 2abcosC$

Rearranging this equation, we can find the value ∠C as shown below.

$\cos C = \frac{a^{2}+b^{2}-c^{2}}{2ab}$
$C = cos^{-1} (\frac{a^{2}+b^{2}-c^{2}}{2ab})$

We can apply the same reasoning for finding the value of ∠B as shown.

$B = cos^{-1} (\frac{a^{2}+c^{2}-b^{2}}{2ac})$

Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.

$C = cos^{-1} (\frac{22.5^{2}+18^{2}-13.6^{2}}{2(22.5)(18)})$
$C \approx 37.19$

$B = cos^{-1} (\frac{22.5^{2}+13.6^{2}-18^{2}}{2(22.5)(13.6)})$
$B \approx 53.13$

Answer: ∠C = 37.19° and ∠B = 53.13°