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olganol [36]
3 years ago
12

Express the ratio 15 out of 25 as a fraction in simplest form.

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
8 0
We are asked to express the fraction 15/25 to simplest form. To simplify the fraction, we will get the greatest common factor of the two numbers. In this case, the GCF is equal to 5. So we divide both numbers by 5, that is equal to 3/5. answer is C
Alona [7]3 years ago
4 0
Ok to reduce fractions you have the find the Greatest Common Factor of both the denominator and nominator and factor it out. In this case the GCF for 15 and 25 is 5 so you would divide 15 and 25 by 5 to get 3/5
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I have 4 times as much money as my brother has. our total is $55.how much does each of us have?
babymother [125]

Answer:

You have 44$, your brother has 11$.

Step-by-step explanation:

Let x be the amount of money your brother has.

Since you have four times the amount of money your brother has, we can call the amount of money you have 4x.

x+4x=55,\\5x=55,\\x=\boxed{\$11}

Thus, you have:

4(11)=\boxed{\$44}

5 0
2 years ago
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What is the answer for 23x9+(91+7)
mestny [16]

Answer:

305

Step-by-step explanation:

23×9+98

207+98

305

3 0
3 years ago
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An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
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Which of the following is the inverse of y = 3 Superscript x?
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Answer:

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