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elena-s [515]
2 years ago
13

Please does anyone know the correct answer choice for this question!!!????

Mathematics
2 answers:
Firlakuza [10]2 years ago
6 0
Answer:(3,-2) so the first point
irina1246 [14]2 years ago
4 0

Answer:

(3:-2) bc u must substitute -2 in for y in the 2th equation

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What is 1,562 divided by 34
marishachu [46]
This would be 45.9
 Get a calculator or try long division :-)
3 0
3 years ago
Read 2 more answers
Fill the missing number to make each expression equal. +2=16+3?
WARRIOR [948]

Answer:

14

Step-by-step explanation:

14+2=16+3

3 0
3 years ago
Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam
kompoz [17]

For this case, we perform the conversions:

First roll:

1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x

x = \frac {3 * 100} {1}\\x = 300 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71

You can pack 71 boxes.

Second roll:

1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11

You can pack 11 boxes.

Thus, in total you can pack11 + 16 + 71 = 98 \ boxes

Answer:

98 boxes

4 0
3 years ago
A 25-foot-long footbridge has two diagonal supports that meet in the center of the bridge. Each support makes a 65∘ angle with a
mamaluj [8]
The length x of a diagonal support, to the nearest tenth of a foot?

x≈ 13 feet

Cuz I said so
5 0
1 year ago
What is the equation for this graph’s lone of best fit. <br> this is due today pls help
Natasha2012 [34]

Answer:

I don't know if your question is multiple choice or not but here's a close estimate to what it should be.

y = \frac{3}{4} x  

Step-by-step explanation:

Obviously at a drop of 0 height there would be 0 rebound height so your y-intercept has to be 0.

As for the slope of the line I used the point at 2.5 and 3.

Here are the coordinates (2.5, 1.25) and (3, 1.625)

Find the average rate of change as you see below

1.625 - 1.25 = .375

3 - 2.5 = .5

.375 / .5 = .75 or 3x/4

The points aren't exactly on the line and the graph isn't 100% linear so obviously the equation is not 100% precise. The slope should very close to 0.75 or 3/4.

3 0
3 years ago
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