Answer:
2$ I think
Step-by-step explanation:
Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
It’s equal to 45/100 which equals 9/20
Answer:
15.9%
Step-by-step explanation:
Percent decrease formula =
(Initial value - New value/Initial value) × 100
Initial value = 9200kg
New value = 7739.4kg
Percent decrease = (9200 - 7739.4/9200) × 100
Percent decrease = (1460.6/9200) × 100
Percent decrease = 15.8760869565%
Approximately = 15.9%
The percent of decrease in the amount of strawberries used annually is 15.9%
