Answer: I am in 6th grade and I just did this test too at K12 CAVA. I got the answer correct, it is:
376
Hope this helps.
<h2>
ANSWER:</h2>
<em>I wonder if you have your equation wrong, because(a−b)2=(a−b)(a−b)=a2−ab−ba+b2=a2–2ab+b2</em>
<em> </em>
<em> Your equation, on the other hand, is (a+b)2 and that is not equal to (a−b)2 except when ab=0, i.e. when either a or b equals 0, and that is not what we normally mean by “prove”. Prove would imply “for all values of a and b”, which is not the case in the form you have your equation,</em>
<em><u>hope </u></em><em><u>you </u></em><em><u>undestood</u></em><em><u> </u></em><em><u>what </u></em><em><u>i </u></em><em><u>meant.</u></em><em><u>. </u></em>
<em><u>then </u></em><em><u>plz </u></em><em><u>like </u></em><em><u>and </u></em><em><u>follow </u></em><em><u>me.</u></em><em><u>. </u></em><em><u>♥</u></em>
X would be 1392. All you do is the opposite: multiplication! 87*16=1392.1392/87=16. Hope this helps! ^_^
Answer:
Part A
Eagle = 6 lbs * 60%
= 6 * 0.6
= 3.6 pounds
Bear = 105 lbs * 25%
= 105 * 0.25
= 26.25 pounds
3.6 + 26.25 = 29.85 pounds
Part B
Percent Increase = Change/Original * 100
= 10/105 * 100
= 9.52%
<h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
If Alex cut his wire 18 times, he ended up with 19 equal pieces. He kept 7, so has 7/19 of his 1/3 of the wire.
Bob cut his wire 20 times, so ended up with 21 pieces, of which he kept 9. So he has 9/21 = 3/7 of his 1/3 of the wire.
Claudia kept 1/13 of her 1/3 of the wire, so has the smallest piece.
Bob kept (3/7)·(1/3)·126 cm = 18 cm.
Alex kept (7/19)·(1/3)·126 cm ≈ 15.47 cm.
Bob kept the longest part of the original wire.
