Answer:
68% of pregnancies last between 250 and 282 days
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 266
Standard deviation = 16
What percentage of pregnancies last between 250 and 282 days?
250 = 266 - 16
250 is one standard deviation below the mean
282 = 266 + 16
282 is one standard deviation above the mean
By the Empirical Rule, 68% of pregnancies last between 250 and 282 days
3. a) p∝1/m
P=k/m
48=k/9
48×9=k
k=432
the equation is: p=432/m
b) p∝1/m
P=k/m
P=432/12
P=36
Ummm I think it is 2 hours and 3 miles for the van for the truck I don’t know and I don’t know
For the figure on the left, the answers are a = 8 and b = 4
This is a 30-60-90 triangle. The short leg is always opposite the smallest angle (30 degrees). The rule is the smallest side is opposite the smallest angle. Similarly, the largest side is opposite the largest angle. In a right triangle the largest side is always opposite the 90 degree angle. This side is the hypotenuse.
Recall that the longer leg is sqrt(3) times the short leg. The notation "sqrt" is shorthand for "square root".
So long leg = (short leg)*sqrt(3) which means b = 4 must be the case to end up with long leg = 4*sqrt(3)
The hypotenuse is twice that of the short leg, so a = 2*b = 2*4 = 8
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For the figure on the right, the answers are x = 2*sqrt(3) and y = 2
The short leg is y, which is opposite the 30 degree angle (this is another 30-60-90 triangle). So y is half of the hypotenuse 4. That explains how y = 2.
The long leg x is equal to sqrt(3) times the short leg, so
(long leg) = (short leg)*sqrt(3)
x = y*sqrt(3)
x = 2*sqrt(3)
Your answer is correct. Good job.
