The answer should be 62 °
180°-118°=62°
Subtract 118° from 180° because a parallel line is 180°. So you just have to find the other side of the line.
Hope this helps.
Answer:
Step-by-step explanation:
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Answer:
a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4
b.p=0.0026,total defects=2.6
c.Less of the items produced will be classified as defects.
Step-by-step explanation:
a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.
![\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z](https://tex.z-dn.net/?f=%5Cmu%3D10%2C%5Csigma%3D0.15%5C%5CTherefore%3A-%5C%5Cz%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3D%5Cfrac%7B9.85-10%7D%7B0.15%7D%5Capprox-1.0%5C%5Cz%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3D%5Cfrac%7B10.15-10%7D%7B0.15%7D%5Capprox%2B1.0%5C%5CP%28x%3C9.85%2Fx%3E10.15%29%3DP%28Z%3C-1.0%2FZ%3E%2B1.0%29%5C%5C%3D2P%28Z%3C-1.0%29%3D2%280.1587%29%3D0.3174%5C%5C)
Total defects=Production*Probability
=0.3174*1000
![=317.4](https://tex.z-dn.net/?f=%3D317.4)
b. ![\mu=10,\sigma=0.05](https://tex.z-dn.net/?f=%5Cmu%3D10%2C%5Csigma%3D0.05)
therefore:-
![z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.05}\approx-3.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.05}\approx+3.0\\\\=P(x10.15)=P(Z+3.0)\\=2P(Z](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3D%5Cfrac%7B9.85-10%7D%7B0.05%7D%5Capprox-3.0%5C%5Cz%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3D%5Cfrac%7B10.15-10%7D%7B0.05%7D%5Capprox%2B3.0%5C%5C%5C%5C%3DP%28x%3C9.85%2Fx%3E10.15%29%3DP%28Z%3C-3.0%2FZ%3E%2B3.0%29%5C%5C%3D2P%28Z%3C--3.0%29%3D2%280.0013%29%5C%5C%3D0.0026%5C%5C)
Defects=Probability*Production
=0.0026*1000
=2.6
c.Reducing process variation results in a significant reduction in the number of unit defects.
Answer:
I'm assuming it's like this : 5*2/25 which will be 0.4, which is 40%
I Think The answer is c I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you