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BigorU [14]
3 years ago
10

Not sure how to do this. i always struggle with proofs.

Mathematics
1 answer:
nlexa [21]3 years ago
5 0

Answer:

Statement: angle QAU congruent to angle KAC

Reasoning: vert. angle congruenct thm

S: angle U congruent to angle C

R: Alt. Int. Angle Thm

S: Triangle QUA similar to Triangle KCA

R: AA Sim. Thm

Step-by-step explanation:

Practice a lot of proofs and you'll start seeing a pattern in them and it will become way easier.

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What is the solution set of |–x| = –10?
dem82 [27]
|a| = b gives
a =b or a = -b

so,
|-x| = -10
gives
-x = -10 or -x = 10
x = 10, -10

now let us verify,
when x = 10, |-10| = +10 and it is not = -10
so, x= 10 is NOT a solution.

when x = -10, |-(-10)| = |10| = 10 and it is not = -10
so, x= -10 is NOT a solution.

hence, this equation does not have a solution.

If we know that |...| can never be negative, we can directly deduce that this equation does not have any solution.
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3 years ago
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BRAINLIEST AND 20 POINTS
Ne4ueva [31]

Answer:

C!

Step-by-step explanation:

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Idk how to do my hw
solniwko [45]

What is your homework?

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3 years ago
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For each system of equations, drag the true statement about its solution set to the box under the system?
natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

 of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

   coefficients of x and y are the same and the numerical terms

   are the same

- The system of equation has one solution if at least one of the

  coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

  numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

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Which equation has the same solution as x2 - 6x – 14 = 0?
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Ion ducking know papi
I’m gonna is your gonna I was like I
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