Add the last two equations to eliminate <em>x</em> :
(<em>x</em> - 2<em>y</em> - 3<em>z</em>) + (- <em>x</em> + <em>y</em> + 2<em>z</em>) = 0 + 3
- <em>y</em> - <em>z</em> = 3
<em>y</em> + <em>z</em> = -3
Subtract this from the first equation to eliminate <em>z</em>, then solve for <em>y</em> :
(2<em>y</em> + <em>z</em>) - (<em>y</em> + <em>z</em>) = -8 - (-3)
<em>y</em> = -5
Plug this into the first equation to solve for <em>z</em> :
2(-5) + <em>z</em> = -8
<em>z</em> = 2
Plug both of these into either the second or third equations to solve for <em>x</em> :
<em>x</em> - 2(-5) - 3(2) = 0
<em>x</em> = -4
Step-by-step explanation:
Answer:
x-intercept 
and y-intercept 
Step-by-step explanation:
I don't know if this is exactly what you were looking for if it's not I'm sorry if so hope this helps have a good rest of your day :) ❤
Square piramid ,triangle prism.
Step-by-step explanation:
Sin^2 (x) * Cos^2 (x) = {[1 - cos (2x)]/2}*{[1 + cos (2x)]/2}
Sin^2 (x) * Cos^2 (x) =[ 1 - cos^2 (2x)]/4
Sin^2 (x) * Cos^2 (x) = (1/4) - (1/4) * cos^2 (2x)
Sin^2 (x) * Cos^2 (x) = (1/4) - (1/4) * {[1 + cos (2*2x)]/2}
Sin^2 (x) * Cos^2 (x) = (1/4) - (1/8) * [1 + cos (4x)]
Sin^2 (x) * Cos^2 (x) = (1/4) - (1/8) - (1/8)* [cos (4x)]
Sin^2 (x) * Cos^2 (x) = (1/8) - (1/8)* [cos (4x)]
