Question

An employment research company estimates that the value of a recent MBA graduate to an accounting company is

Answer 1

Answer:

(de/dt) = 0.70929

Step-by-step explanation:

Given

V = 4*e² + 4*g³

where

• V is the value of the graduate

• e is the number of years of prior business experience
• g is the graduate school grade point average

If V = 300 (constant)

g = 2.9

dg/dt = - 0.4

de/dt = ?

we have to get e as follows

V = 4*e² + 4*g³ ⇒  (V/4) = e² + g³  ⇒ e = √((V/4) - g³)

⇒ e = √((300/4) - (2.9)³)

⇒ e = 7.1141

Then we apply

dV/dt = d(4*e² + 4*g³)/dt

d(300)/dt = 4*((2*e*de/dt) + 3*g²*(dg/dt))

0 = (2*e*de/dt) + 3*g²*(dg/dt)

⇒ 0 = 2*(7.1141)*(de/dt) + 3*(2.9)²*(- 0.4)

⇒   (de/dt) = 0.70929