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maw [93]
3 years ago
11

How do I solve it by substitution?y=-24x-6y=-20

Mathematics
2 answers:
iris [78.8K]3 years ago
8 0
-2x6=-12 so then ?x4=-8 and that something is -2
Ostrovityanka [42]3 years ago
3 0
I hope this helps you! :)

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Suppose you are going to graph the data in the table: Minutes Temperature (°C) 0 −2 1 1 2 3 3 4 4 5 5 −4 6 2 7 −3 What data shou
Gelneren [198K]

Answer:

See below

Step-by-step explanation:

Minutes            Temperature

 0                          -2

  1                           1

  2                          3

  3                          4

  4                          5

 5                           -4

 6                           2

  7                          -3

Minutes should be graphed on x - axis as it repeatedly increases by 1 and seems to be independent. (Remember the independent variable is on x-axis). The axis increment should be one as told before, that the terms are increasing by 1.

Now, Temperature should e graphed on y-axis because it seems to depend on Minutes. The axis increment should also be 1 for this as although, it not increasing by 1 but still at some points increases by 1. So, the axis increment should be 1 for Temperature.

6 0
3 years ago
A projectile is thrown upward so that its distance above the ground after t seconds is h =-13t2 + 390t. After how many seconds d
sertanlavr [38]

Answer:

<h3>The option C) 15 s is correct</h3><h3>Therefore the maximum height it reaches in <u>15 seconds. </u></h3>

Step-by-step explanation:

Given equation is h =-13t^2 + 390t

Given that a projectile is thrown upward so that its distance above the ground after t seconds is h =-13t^2 + 390t

<h3>To find how many seconds does it reach its maximum height:</h3>

"The standard form of a parabola's equation is  expressed as :

y=ax^2+bx+c.

If a>0, then the parabola opens upwards;

if a the parabola opens downwards."

The maximum height is the vertex of the parabola  h =-13t^2 + 390t which is \frac{-b}{2a}.

Comparing the given equation with the standard form of parabola we get

the values of a=-13 , b=390 and c=0

The maximum height in t=\frac{-b}{2a}.

Substitute the values we get

t=-\frac{390}{2(-13)}

=\frac{390}{26}

=15

<h3>∴ t=15 s</h3><h3>∴ The option C) 15 s is correct.</h3><h3>∴ the maximum height is the vertex of the parabola, at t reaches in 15 seconds. </h3>
3 0
3 years ago
Anyone wanna help me??
klasskru [66]
Answer

i believe it’s b

expiation
3 0
3 years ago
Both lines pass through the point (-3,-4). one has a slope of 4 and the other has a slope of -1/4
Alchen [17]
If the question is to find the slope-intercept form of both lines, here's the answer:
Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point.
Let's first apply all these for the first line, with a slope of 4.
y = mx + b
y=-3; x=-4; m=4. All we need to do is find b.
-3 = 4(-4) + b
-3 = -16 + b
b=13
So the equation of the first line is y= 4x + 13.

Now, we'll do the same thing but for the second line:
y=-3; x=-4; m=-1/4, and we need to find b.
-3 = (-1/4)(-4) + b
-3 = 1 + b
b= -4
So the equation of the second line is y=(-1/4)x - 4

Hope this Helps! :)
3 0
4 years ago
Please help I’ll mark brainliest
Aleonysh [2.5K]
Use y=mx+b

m = 4
x = 0
y = -1

-1 = (4)(0) + b
^^^
Multiply
6 0
3 years ago
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