There are several methods of rounding, but in this case the 'best' one is probably to round up. Rounding down suggests that Kathy actually ran faster.
<span>26.2 (mile) * 6.2 (minutes/mile) = 162.44 rounded up => 163 minutes.</span>
Given:
Radius = 7cm
Central angle (theta) = 40 degrees
Asked:
Arc length (s)
SOLUTION:
s = 2*pi*radius*(central angle/360)
s = 2(3.14)(7cm)(40 degrees/360 degrees)
s = 4.88 cm
Therefore, the arc length of the circle is 4.88 centimeters.
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So if triangle ABC is similiar to triangle DEC then we know that when two figures are similar, the ratios of the lengths of their corresponding sides are equal.So we can write:
AC/DC = BC/EC =AB/DE = k
BC= 9ft + 6ft = 15
BC/EC= k
15/6=k
Now that we know the k we can find the height of the tree that's equal to AB:
AB/DE= k
AB/4=15/6
6AB= 15 x 4
AB= 60/6 = 10
The height of the tree is 10ft
Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78
Area of a Rectangle = Length * Width
Length= 17 yards
Width= ?
L*W=A
17 yards * 2 yards = 34 square yards