In this problem, you are asked to find the area of the
trapezoid. The formula in finding the area of the trapezoid is:
A = [(a + b)/2] x h
Where a = base 1
b = base
2
h =
height
Substituting the given measurements to the formula:
A = [(1.7 m + 6.7 m) / 2] x 5 m
A = (8.4 m / 2) x 5 m
A = 4.2 m x 5 m
A = 21 m^2
Therefore, the area of the trapezoid is 21 square meters.
So each dimention is 32 by 8 by 10
so the surface area=2 times(8 times 10)+(2 times (32 times 10))+(2 times (8 times 32))=2 times 80+2 times 320+2 times 256=1312
if halved
just divide each by 2
(2 times 4 times 5)+(2 times 16 times 5)+(2 times 4 times 16)=(2 times 20)+(2 times 80)+(2 times 64)=40+160+128=328
the new surface area is 328 mm^2
Answer:
m∠SVT = 79*
Step-by-step explanation:
8y - 33 = 5y + 9
8y = 5y + 42
3y = 42
y = 14
_____
5y + 9
5(14) + 9
70 + 9
79
The bicyclist travels 90 miles in 5 hours
90÷18=5
I believe the answer is 4
