What equivalent fractions does the model show?
1 answer:
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(6y - 11)(6y + 11) = ay² - b |use (a - b)(a + b) = a² - b²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
Answer:
The number of texts she can have is less than 600.
Step-by-step explanation:
Total monthly charge
30 + 0.05 for each text.
So, for x tests, the charge is:
Write an inequality to represent the # of texts she can have?
It has to be under 60, so:
The solution is:
The number of texts she can have is less than 600.