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3 years ago

Determine the measures of angle ACB, angle DCE, & Angle BCD.

Mathematics

1 answer:

ruslelena [56]3 years ago

7 0

Answer: ∠ACB= 60°, ∠DCE= 65°, ∠BCD= 55°

Step-by-step explanation:

1) Since ΔABC is an equilateral, we know ∠ACB= 60°

2) Since we know ΔCDE is an isosceles, we know that ∠DCE= 1/2 (180-50), which is 65°

3) We can add the 2 angles and then subtract them from 180 degrees to get ∠BCD= 55°

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Write 1/3(12x-6)+x in standard form

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Zinaida [17]

Answer:

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4 years ago

Solve x2 – 12x + 59 = 0 for x.

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3 years ago

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Answer:

Step-by-step explanation:

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The ratio of the diameters is 15:11. If the diameter of the smaller ball is 55cm, what is the volume of the larger ball? Round t

gizmo_the_mogwai [7]

Answer:

220,781.25 cubic cm

Step-by-step explanation:

Given ratio of the diameters = 15:11

Let the actual value of of diameters be 15x and 11x to maintain the ratio of 15:11

Given that smaller one has diameter of 55cm

thus 11x = 55cm

x = 55/11 cm = 5

Thus, diameter of larger ball = 15xcm= 15*5cm =75cm.

we know that radius is half of diameter

Radius = diameter/2

Thus radius of larger ball = 75/2 cm = 37.5 cm.

Volume of sphere is given by $(4/3)\pi r^3$

we know that ball has spherical shape

thus volume of larger ball is calculated as given below

$volume \ of \ ball = (4/3)\pi r^3\\=> volume \ of \ ball = (4/3)*3.14* 37.5^3\\=> volume \ of \ ball = (4/3)*3.14* 37.5^3\\=> volume \ of \ ball = 220,781.25$

Thus, volume of larger ball is 220,781.25 cubic cm

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3 years ago