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Tanya [424]
3 years ago
13

A hockey team scored 45 goals in its first 16 games. At this rate, how many goals would the team score in an 80 game season? A.

50 B. 109 C. 141 D. 225
Mathematics
1 answer:
Goshia [24]3 years ago
6 0
First you have to divide 45 by 16. that gives us 2.8125. then multiply 2.8125 by 80 to get 225.
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98-12+e <br> =106<br> Need help quick
Serjik [45]

Answer:

98 - 12 + e = 106 \\ 86 + e = 106 \\ e = 10 6 - 86 \\ e = 20

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ.

6 0
2 years ago
when the base of a ladder is placed 10ft away from the base of a building, the top of the ladder touches the building at 18ft ab
Vikki [24]
35 feet i think i’m not sure
6 0
2 years ago
In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




5 0
3 years ago
True or false the sum of two negative numbers is always negative explain why or why not this is true or false
erma4kov [3.2K]

Answer:

true

Step-by-step explanation:

Let's say you have -7 dollars in your bank account, and then you go and spend 5 more, which is -5, now you have -12 bucks in your account

3 0
3 years ago
Read 2 more answers
What is the fourth term in the binomial expansion of (2x – y) 7?
nata0808 [166]

Answer:

(7C4) (2x)^4 (-y)^{7-4}

And replacing we got:

35 (2^4) x^4 (-y)^{-3}

And then the final term would be:

-560 x^4 y^3

Step-by-step explanation:

For this case we have the following expression:

(2x-y)^7

And we can use the binomial theorem given by:

(x+y)^n =\sum_{k=0}^n (nCk) x^k y^{n-k}

And for this case we want to find the fourth term and using the formula we have:

(7C4) (2x)^4 (-y)^{7-4}

And replacing we got:

35 (2^4) x^4 (-y)^{-3}

And then the final term would be:

-560 x^4 y^3

8 0
2 years ago
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