Question

Based on the survey results from 300 selected students in the Burbank School District (BSD), the 98% confidence interval used to estimate the population proportion of all BSD students who have access to a working computer at home was computed to be 48% to 60%. The following 2 subquestions require a numeric input, no work is necessary. [2 points] What number of students (out of the 300 sampled) have access to a working computer at home

Answer 1

Answer:

follows are the solution to this question:

Step-by-step explanation:

Please find the correct question in the attached file:

The formula for calculating the Confidence interval of proportion:

$\to CI=\hat{p} \pm Z_{\frac{\alpha}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\\to \hat{p}=\frac{\text{lower limit +upper limit}}{2}$

      $=\frac{0.48+0.60}{2}\\\\=\frac{1.08}{2}\\\\=0.54$

The number of learners with access to working at home on a computer:

$= 0.54 \times 300 \\\\=162$

Lower limit =0.48

upper limit = 0.60

$\to margin \ error = \frac{\text{upper limit - lower limit}}{2}$

                          $=\frac{0.60-0.48}{2}\\\\=\frac{0.12}{2}\\\\= 0.06$