Answer:
$3 max
Step-by-step explanation:
Charge= b, Customer= c, Revenue= r
r= bc, currently, r= 16*10= $160
We know that: b+1 ⇒ c-2 and the target is r ≥ 130
So, this will all be reflected as:
b=10+x ⇒ c= 16-2x
- (10+x)(16-2x) ≥ 130
- 160 -20x +16x - 2x² ≥ 130
- -2x² - 4x + 30 ≥ 0
- x² + 2x -15 ≤ 0
- (x+1)² ≤ 4²
- x+1 ≤ 4 (negative value not considered)
- x ≤ 3
As we see the max increase amount is $3, when the revenue will be:
(10+3)*(16-3*2)= 13*10= $130
A polynomial expression can only be categorized into a function if and only if a single input can only have one and only output. This means that there should be no more than one dissimilar values of y for the same value of x.
Evaluating the givens above, it can be observed that there are two -1's as an x-coordinate and it has two outputs, 0 and 1. Thus, we can remove either (-1,0) or (-1,1) for the relationship to become a function.
Subtract 1111 from both sides
5{e}^{{4}^{x}}=22-115e4x=22−11
Simplify 22-1122−11 to 1111
5{e}^{{4}^{x}}=115e4x=11
Divide both sides by 55
{e}^{{4}^{x}}=\frac{11}{5}e4x=511
Use Definition of Natural Logarithm: {e}^{y}=xey=x if and only if \ln{x}=ylnx=y
{4}^{x}=\ln{\frac{11}{5}}4x=ln511
: {b}^{a}=xba=x if and only if log_b(x)=alogb(x)=a
x=\log_{4}{\ln{\frac{11}{5}}}x=log4ln511
Use Change of Base Rule: \log_{b}{x}=\frac{\log_{a}{x}}{\log_{a}{b}}logbx=logablogax
x=\frac{\log{\ln{\frac{11}{5}}}}{\log{4}}x=log4logln511
Use Power Rule: \log_{b}{{x}^{c}}=c\log_{b}{x}logbxc=clogbx
\log{4}log4 -> \log{{2}^{2}}log22 -> 2\log{2}2log2
x=\frac{\log{\ln{\frac{11}{5}}}}{2\log{2}}x=2log2
Answer= −0.171
Your answer is 5.499.
Hope you do well on whatever it is, and glad I could help :)
A = 1/2h(b1 + b2)
A = 1/2*9.28(10.5 + 21.1)
Using calculator
A = 146.624 square cm
