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algol13
2 years ago
8

9. Which of the following is TRUE? ( 5 points) a. For a data set with mean = 25 pounds and Standard Deviation = 2 pounds then 95

% of the data is between 23 pounds and 27 pounds. b. For a data set with mean = 25 pounds and Standard Deviation = 3 pounds then 95% of the data is between 22 pounds and 28 pounds. c. For a data set with mean = 25 pounds and Standard Deviation = 3 pounds then 65% of the data is between 19 pounds and 31 pounds. d. For a data set with mean = 25 pounds and Standard Deviation = 3 pounds then 95% of the data is between 19 pounds and 31 pounds.
Mathematics
1 answer:
pychu [463]2 years ago
4 0

Answer:

For a data set with mean = 25 pounds and Standard Deviation = 3 pounds then 95% of the data is between 19 pounds and 31 pounds.

Step-by-step explanation:

1 ) 68% of the data lies within 1 standard deviation of mean  

This means 68% of data lies between:\mu-\sigmato \mu+\sigma

2) 95% of the data lies within 2 standard deviation of mean  

This means 95% of data lies between:\mu-2\sigmato \mu+2\sigma

3) 99.7% of the data lies within 3 standard deviation of mean

This means 99.7% of data lies between:\mu-3\sigma to\mu+3\sigma

Now,

95% of the data lies within 2 standard deviation of mean  :

For Mean = \mu = 25

Standard deviation = \sigma = 2

So,  95% of data lies between:25-2(2)to 25+2(2)

95% of data lies between:21to 29

For Mean = \mu = 25

Standard deviation = \sigma = 3

So,  95% of data lies between:25-2(3)to 25+2(3)

95% of data lies between:19to 31

So, Option D is true

For a data set with mean = 25 pounds and Standard Deviation = 3 pounds then 95% of the data is between 19 pounds and 31 pounds.

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Questions Below. Would Appreciate Help!
kherson [118]

Answer:

The function that could be the function described is;

f(x) = -10 \cdot cos \left (\dfrac{2 \cdot \pi }{3} \cdot x \right ) + 10

Step-by-step explanation:

The given parameters of the cosine function are;

The period of the cosine function = 3

The maximum value of the cosine function = 20

The minimum value of the cosine function = 0

The general form of the cosine function is presented as follows;

y = A·cos(ω·x - ∅) + k

Where;

\left | A \right | = The amplitude = Constant

The period, T = 2·π/ω

The phase shift, = ∅/ω

k = The vertical translation = Constant

Therefore, by comparison, we have;

T = 3 = 2·π/ω

∴ ω = 2·π/3

The range of value of the cosine of an angle are;

-1 ≤ cos(θ) ≤ 1

Therefore, when A = 10, cos(ω·x - ∅) = 1 (maximum value of cos(θ)) and k = 10, we have;

y = A × cos(ω·x - ∅) + k

y = 10 × 1 + 10 = 20 = The maximum value of the function

Similarly, when A = 10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, we get;

y = 10 × -1 + 10 = 0 = The minimum value of the function

Given that the function is a reflection of the parent function, we can have;

A = -10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, to get;

y = -10 × -1 + 10 = 20 = The maximum value of the function

Similarly, for cos(ω·x - ∅) = 1 we get;

y = -10 × 1 + 10 = 0 = The minimum value of the function

Therefore, the likely values of the function are therefore;

A = -10, k = 10

The function is therefore presented as follows;

y = -10 × cos(2·π/3·x) + 10

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