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3 years ago

The graph of f(x) = 2^x + 3 shifts 10 units to the right when it is replaced with the graph of f(x) = 2^x − k.

Mathematics

2 answers:

Yuri [45]3 years ago

6 0

The answer would still be 3. Nothing changes

Volgvan3 years ago

5 0

Answer:

Is the answer 7 or 3 or 10 or 13 so far there are a lot of people saying a lot of different things ive Got ppl saying 7 3 10 and 13 wots the answer?

Step-by-step explanation:

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Kara mixes different colors of paint to create new colors. The table shows the amount of paint Kara mixes per batch.

Sergio [31]

Answer:

D. Batch 5.

Step-by-step explanation:

The batch should have the same proportion of blue to white to yellow.

In Batch 1, there are two parts of blue, 1.5 parts of white, and 1 part of yellow.

In Batch 5, there are four parts of blue, 3 parts of white, and 2 parts of yellow.

4 / 2 = 2

3 / 2 = 1.5

2 / 2 = 1

Since the proportions are equal to those found in Batch 1, D. Batch 5 will create the same colors as the first batch.

Hope this helps!

8 0

3 years ago

What is the domain of the function represented by the graph?

nalin [4]

Answer:

I believe its c

Step-by-step explanation:

The domain of a quadratic function is all real numbers

8 0

3 years ago

Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal

pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and $\frac{11}{6}$ .

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form $f(x) = 0$ based on the following formula:

$x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}$

Where:

$x_{i}$ - i-th Approximation, dimensionless.

$x_{i+1}$ - (i+1)-th Approximation, dimensionless.

$f(x_{i})$ - Function evaluated at i-th Approximation, dimensionless.

$f'(x_{i})$ - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be $f(x) = x^{2}-8$ and $f'(x) = 2\cdot x$ , the resultant expression is:

$x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}$

First iteration: ( $x_{1} = 2$ )

$x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}$

$x_{2} = 2 + \frac{4}{4}$

$x_{2} = 3$

Second iteration: ( $x_{2} = 3$ )

$x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}$

$x_{3} = 2 - \frac{1}{6}$

$x_{3} = \frac{11}{6}$

7 0

4 years ago

(BRAINLIEST) The Arcadia Theater charges $4 for adult tickets and $3 for student tickets. Mr. Steele purchased 9 tickets (some s

tekilochka [14]

Answer:

Step-by-step explanation:

Please mark brainliest

8 0

3 years ago

Read 2 more answers

Me pueden ayudar en esta ecuación bicuadratica, porfaaa: 9p⁴=—12x²—6/9

Dominik [7]

Answer:

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Step-by-step explanation:

Pregunta correcta

¿Me pueden ayudar en esta ecuación biquadratica, por favor: 9x⁴ = —12x² - 6/9

Solución

9x⁴ = —12x² - 6/9

9x⁴ + 12x² + 6/9 = 0

multiplicar por 9

81x⁴ + 108x² + 6 = 0

Deje x² = y, entonces x⁴ = y²

81y² + 108y + 6 = 0

Resolviendo esta ecuación cuadrática

y = -0.0581 o y = -1.275

Recordemos, x² = y

x = ±√y

Si y = -0.0581

x = ± √(-0.0581) = ± 0.241i = 0.241i o -0.241i

Si y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i o -1.129i

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

¡¡¡Espero que esto ayude!!!

Correct Question

Can you help me in this biquadratic equation, please: 9x⁴ = —12x² — 6/9

Solution

9x⁴ = —12x² — 6/9

9x⁴ + 12x² + 6/9 = 0

multiply through by 9

81x⁴ + 108x² + 6 = 0

Let x² = y, then x⁴ = y²

81y² + 108y + 6 = 0

Solving this quadratic equation

y = -0.0581 or y = -1.275

Recall, x² = y

x = ±√y

If y = 0.0581

x = ±√(-0.0581) = ±0.241

If y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i or -1.129i

Hence x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Hope this Helps!!

5 0

3 years ago