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BlackZzzverrR [31]
3 years ago
5

According to the map on the left, Central Park is about 50 blocks long by 9 blocks wide. What is the approximate area of the par

k? Show your work.

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0
50*9
=450
Rounded: 500
About 500 should be the area
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14n-2(2-3n)+4(3n-1)+2(4n-6)<br> What is the simplest form of this equation?
Artemon [7]

Answer: 40n-20

Step-by-step explanation:

14n-4+6n+12n-4+8n-12

14n+6n+12n+8n-4-4-12

40n-20

6 0
3 years ago
At approximately what value of x do the two lines meet?
Alexus [3.1K]

Answer:

the two lines are meeting at the co-ordinate (-1, -1)

(x, y) = (-1,-1)

therefore, the value of x is -1.

8 0
3 years ago
If y=8 when x=4 find y when x=5
djyliett [7]

Answer:

y = 10 when x = 5

Step-by-step explanation:

When x = 4, y = 8

Simplify. Divide 4 from both x and y

x = 4/4 = 1

y = 8/4 = 2

when x = 1, y = 2

Next, solve for when x = 5. Mutliply 5 to both x and y

x = 1 * 5 = 5

y = 2 * 5 = 10

y = 10 when x = 5

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7 0
3 years ago
Read 2 more answers
GEOMETRY HELP!
stiks02 [169]

The answer is 12. I would do it by setting up a proportion:

8 = x

10 15

Then cross multiply to get

10x=8*15

10x=120

x=12

3 0
4 years ago
A certain forest covers an area of
iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year  4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year  5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year  6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0
3 years ago
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