The area formula of a circle is
× π.
With that being said, we can solve both problems!
Starting with part A:
-The radius we know is 21cm. From there, we can substitute in our formula with the new value.
x π
From there, we can square our radius:
(21 x 21) x π
(441) x π
And finally, we can multiply by pi to get our answer.
(441) x π
1385.44236023
Which rounded to the nearest tenth is 1385.4. Therefore, the area of the porthole is 1385.4 centimetres.
The second part can be followed with the same process, hopefully you understand the concept enough to where you're comfortable solving problems like this on your own. Feel free to reach out if you have any further trouble!
<em>Hope this helped! :)</em>
Answer:
9. 5 Hours
Step-by-step explanation:
8:30 AM to 12:00 PM = 3.5 hours
12:00 PM to 6:00 PM = 6 hours
Total = 6 + 3.5 = 9.5 hours
Hope this answer helps you :)
Have a great day
Mark Brainliest
Answer:
i think 24 cm² is answer good luck
Answer:
12 miles per hour
Step-by-step explanation:
Let speed of boat in still water be "x"
and speed of current be "c"
So, downstream rate would be "x + c"
And, upstream rate would be "x - c"
Now, given c = 4
We can use the distance formula, D = RT, where
D is distance, R is rate, and T is time
to solve this.
Downstream:
D = RT
92 = (x+4)(t)
Upstream:
D = RT
46 = (x-4)(t)
Both the times are same, we can equate both the times. Lets simplify first:
t = 92/(x+4)
and
t = 46/(x-4)
Equate:

Now, cross multiply and solve for x to get our answer:

Speed of Boat (in still water) = 12 mph
Answer:
P(P, then Y)=(1/11)(1/10)=1/110
Step-by-step explanation:
The number of letters in probability is 11.
There is 1 P.
The probability of drawing a P on draw 1 is the number of ways of drawing a P, which is 1, divided by the number of ways of drawing any letter, which is 11. Thus:
Probability of drawing a P on the first draw is 1/11.
There are now 10 letters left. There is 1 Y. so
Probability of drawing a Y on the second draw given that you drew a P on the first draw is 1/10.
The probability of drawing a P on the first draw and a Y on the second draw is
(probability of a P on draw 1)(probability of drawing a Y on draw 2, given a P on draw 1)
P(P, then Y)=(1/11)(1/10)=1/110