A certain forest covers an area of
1 answer:
Answer:
2598 square kilometers
Step-by-step explanation:
Hello
Step 1
year one
using a rule of three is possible to find how much is 8.75 od 4500 km2
Let
if
4500 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year one, the area will be
4500-393.75=4106.25
this will be the initial area for the year 2.
Step 2
repite the step 1 with area initial =4106.25 km2
4106.25 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year 2, the area will be
4106-359.29=3746.70
this will be the initial area for the year 3.
Step 3
repite the step 1 with area initial =4106.25 km2
3746.70 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year 3, the area will be
3746.70-327.83=3419.09
this will be the initial area for the year 4.
Step 4
year four
repite the step 1 with area initial =3419.09 km2
3419.09 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year 4, the area will be
3419.09-299.173=3119.82
this will be the initial area for the year 5.
Step 5
year five
repite the step 1 with area initial =3119.82 km2
3119.82 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year 5, the area will be
3119.82-272.99=2846.92
this will be the initial area for the year 6.
Step 6
year six
repite the step 1 with area initial =2846.92km2
2846.92 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year six, the area will be
2846.92-249.10=2597.82 square kilometers
Have a great day.
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Given list of values
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}
Sort list A to get list B
B = {7, 9, 10, 13, 19, 20, 23, 23, 27, 28, 29, 34, 36, 36, 37, 40, 43}
The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43
Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)
Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
which is the list of all values lower or smaller than the median.
The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1
The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U
------------------------------------------------
Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43
This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1).
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}
Sort list A to get list B
B = {7, 9, 10, 13, 19, 20, 23, 23, 27, 28, 29, 34, 36, 36, 37, 40, 43}
The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43
Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)
Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
which is the list of all values lower or smaller than the median.
The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1
The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U
------------------------------------------------
Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43
This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1).