The answer to this question is 98000
Answer:
could you please explain me the exact question
Answer:
Step-by-step explanation:
Given that: Training-session duration of female rowers with normal iron status is Normally distributed, with mean 69 minutes and standard deviation 18minutes.
Solution:
z score shows the relationship between sample means. The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by the formula:

Given that μ = 69 minutes, σ = 18 minutes, n = 24
For x > 63 minutes:

From the distribution table, P(x > 63) = P(z > -1.63) = 1 - P(z < 1.63) = 1 - 0.0516 = 0.9484
Answer:
Step-by-step explanation:
3 + 2x + 1 = 2x + 3
2x + 4 = 2x + 3
4 ≠ 3
no solution
If we use v for Vidya's age, then the expression (24v)+6