A open education means what you share and customize
Answer: 3/8x
To find the least common denominator first convert all integers and mixed numbers (mixed fractions) into fractions. Then find the lowest common multiple of the denominators. This number is same as the least common denominator .You can then write each term as an equivalent fraction with the same LCD denominator.
Answer:
838860
Step-by-step explanation:
How do you find the sum of the first 10 terms?
To sum up the terms of this arithmetic sequence: a + (a+d) + (a+2d) + (a+3d) +
Example: Add up the first 10 terms of the arithmetic sequence:
a = 1 (the first term)
d = 3 (the "common difference" between terms)
n = 10 (how many terms to add up)
What is the sum of the first 10?
The number series 1, 2, 3, 4 , 9, 10. Therefore, 55 is the sum of positive integers upto 10.
Answer:
2. D. 
1. C. 
Step-by-step explanation:
![\displaystyle 2A_B + h[c + b + a] = S.A.](https://tex.z-dn.net/?f=%5Cdisplaystyle%202A_B%20%2B%20h%5Bc%20%2B%20b%20%2B%20a%5D%20%3D%20S.A.)
Area of a <em>Triangle</em> [keep this in mind to find the base area]:
Pythagorean Theorem [You will need this theorem to find the lengths of both hypotenuses on both triangular bases]:
2. ![\displaystyle 2A_B + p[c + 3 + 4] = 120 → 2[6] + p[5 + 3 + 4] = 120 \\ \\ 12 + 12p = 120 → 108 = 12p; 9 = p](https://tex.z-dn.net/?f=%5Cdisplaystyle%202A_B%20%2B%20p%5Bc%20%2B%203%20%2B%204%5D%20%3D%20120%20%E2%86%92%202%5B6%5D%20%2B%20p%5B5%20%2B%203%20%2B%204%5D%20%3D%20120%20%5C%5C%20%5C%5C%2012%20%2B%2012p%20%3D%20120%20%E2%86%92%20108%20%3D%2012p%3B%209%20%3D%20p)
1. ![\displaystyle 2A_B + 15[c + 6 + 8] = S.A. → 2[24] + 15[10 + 6 + 8] = S.A. \\ \\ 48 + 15[24] = S.A. → 48 + 360 = S.A.; 408 = S.A.](https://tex.z-dn.net/?f=%5Cdisplaystyle%202A_B%20%2B%2015%5Bc%20%2B%206%20%2B%208%5D%20%3D%20S.A.%20%E2%86%92%202%5B24%5D%20%2B%2015%5B10%20%2B%206%20%2B%208%5D%20%3D%20S.A.%20%5C%5C%20%5C%5C%2048%20%2B%2015%5B24%5D%20%3D%20S.A.%20%E2%86%92%2048%20%2B%20360%20%3D%20S.A.%3B%20408%20%3D%20S.A.)
I am delighted to assist you anytime.
N. One cannot be a prime number because it is not higher than one and
