Answer:
The probability that on a randomly selected day the statistics professor will have five messages is 0.1755.
Step-by-step explanation:
Let the random variable <em>X</em> represent the number of e-mail messages per day a statistics professor receives from students.
The random variable is approximated by the Poisson Distribution with parameter <em>λ</em> = 5.
The probability mass function of <em>X</em> is as follows:

Compute the probability that on a randomly selected day she will have five messages as follows:


Thus, the probability that on a randomly selected day the statistics professor will have five messages is 0.1755.
(kg/L)0.001gram per litre (g/L)1
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Hope this helps. :)
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40/1.4=28.57 i think this is right
9514 1404 393
Answer:
Step-by-step explanation:
The angle marks show that ΔRST is isosceles, so RT = RS. They also show ΔRTU to be equilateral, so UT = RT.
UT = RS
x -5 = 15
x = 20 . . . . . . add 5
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ΔRTU is equilateral, so ∠RTU is 60°. The angle marked 3y° is complementary to that.
3y = 30
y = 10 . . . . . divide by 3