F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
Your answer should be 3
Use this formula to solve slopes:
m = (y2<span> – y</span>1) / (x2<span> – x</span>1<span>) </span>
Answer is 10(2k+5)
-----------------------------------
Work Shown:
20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)
Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer
Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
Answer:
Answer: 60%
Step-by-step explanation:
Answer:
x=2
Step-by-step explanation:
i would set up a system of equation using the pythagorean theorem:
1^2+x^2=z^2
4^2+x^2=y^2
Add up these equations to get:
17+2x^2=y^2+z^2
But notice that
y^2+z^2=5^2
So you can substitute
17+2x^2=25
2x^2=8
x^2=4
x=2
:)
