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il63 [147K]
3 years ago
15

sierra has a total of 61 dimes and quarters in her piggy bank. She has 3 more quarters than dimes. how many dimes and how many q

uarters does she have?
Mathematics
1 answer:
CaHeK987 [17]3 years ago
7 0
32 quarters and 29 dimes.
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Find 5(-12)<br> A. -60<br> B. -7<br> C. -50<br> D. 60
erastovalidia [21]

Answer:

The answer is A -60

Step-by-step explanation:

u soppost to multiply 5×-12

7 0
3 years ago
A long distance runner starts at the beginning of a trail and runs at a rate of 6 miles per hour. One hour later, a cyclist star
sasho [114]
The answer to this is 50 minutes. by then the runner has gone 11 miles in an hour and 50min and the cyclist has gone 11 miles also 
5 0
3 years ago
Mason can plant 12 bushes in 60 minutes. How many can he plant in 3 hours?​
Liono4ka [1.6K]

Well first-

Mason planted 12 bushes in one hour, so basically all you have to do is multiply the amount of bushes planted in a hour (12) by the hours (3) so-

12 x 3 = 36 plants for 3 hours

<em>your welcome :)</em>

3 0
3 years ago
Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in
Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms i.e.;

Sample mean, xbar = 290      Sample standard deviation, s = 30  and  Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

                         \sigma^{2}  =  s^{2} = 30^{2}

                          \sigma^{2}  = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of  \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

P(10.12 < \chi^{2}__1_9 < 30.14) = 0.90 {At 10% significance level chi square has critical

                                           values of 10.12 and 30.14 at 19 degree of freedom}        

P(10.12 < \frac{(n-1)s^{2} }{\sigma^{2} } < 30.14) = 0.90

P(\frac{10.12}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{30.14}{(n-1)s^{2} } ) = 0.90

P(\frac{(n-1)s^{2} }{30.14} < \sigma^{2} < \frac{(n-1)s^{2} }{10.12} ) = 0.90

90% confidence interval for \sigma^{2} = [\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]

                                                   = [\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]

                                                   = [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

(c) 90% confidence interval estimate of the population standard deviation is given by ;

       P(\sqrt{\frac{(n-1)s^{2} }{30.14}} < \sigma < \sqrt{\frac{(n-1)s^{2} }{10.12}} ) = 0.90

90% confidence interval for \sigma = [\sqrt{\frac{19s^{2} }{30.14}}   , \sqrt{\frac{19s^{2} }{10.12}}  ]

                                                 = [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0
3 years ago
What is the sum of 2 3/5 - 1 3/8
Natalija [7]
The Sum of 2 3/5-1 3/8 is 1.225
i hoped that helped u. 
8 0
3 years ago
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