Question

The area of a trapezium is 31.5 cm². If the parallel sides are of length 7.5 cm and 5.3 cm, calculate the perpendicular distance between them

Answer 1

Answer:

The answer is 4.9cm

Step-by-step explanation:

To find the perpendicular distance between them that's the height we use the formula

$Area \: \: of \: \: a \: \: trapezium = \frac{1}{2} (a + b) \times h$

where

a and b are the parallel sides of the trapezium

h is the perpendicular distance

From the question

Area = 31.5cm²

a = 7.5 cm

b = 5.3 cm

Substituting the values into the above formula we have

$31 .5 = \frac{1}{2} (7.5 + 5.3) \times h$

$31.5 = \frac{1}{2} \times 12.8h$

$31.5 = 6.4h$

Divide both sides by 6.4

$h = \frac{31.5}{6.4}$

h = 4.921875

We have the final answer

h = 4.9cm

Hope this helps you