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AVprozaik [17]
4 years ago
12

What is the solution set? (0, -2) (2, 0) (7, 0) (5, 3)

Mathematics
2 answers:
Dvinal [7]4 years ago
7 0

Answer:

(5,3)

Step-by-step explanation:

Look for the coordinates of the point of intersection where the 2 graphs cross. This gives the solution.

In this case, they cross at (5,3) and they intersect at only one location (i.e there is only 1 solution)

vivado [14]4 years ago
7 0
I think the answer is (5, 3)
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Answer:

\frac{20}{3}\pi

Step-by-step explanation:

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3 years ago
Find the equivalent to this fraction with the denominator 100
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Answer:

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Step-by-step explanat

3 0
3 years ago
The Candle Factory is producing a new candle. It has a radius of 3 inches and a height of 5 inches. What is the surface area of
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Answer:

We are looking for the amount of wax it will take to fill up that size candle mold to make that candle. That means that we are looking for the volume of wax, and the shape is a cylinder. The volume formula for a cylinder is

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Step-by-step explanation:

6 0
3 years ago
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You paint 1 2 12 wall in 1 4 14 hour. At that rate, how long will it take you to paint one wall
Rudiy27
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3 0
3 years ago
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En la primera fase del proceso selectivo para Al cuerpo de profesores eliminan a cuatro novenos De los aspirantes mientras que e
irina1246 [14]

Answer:

The fraction of the applicants who have passed the two phases of the selection process is \frac{10}{63}.

Step-by-step explanation:

The question is:

In the first phase of the selection process for the body of teachers they eliminate four-ninth of the applicants while in the second phase they eliminate 5/7 of those who passed the first phase. If there were 315 applicants what is the fraction of the applicants who have passed the two phases of the selection process?

The total number of applicants is

<em>N</em> = 315.

It is provided that 4/9th of the applicants were eliminated in the first phase.

Then the fraction of candidates who passed the first phase is:

Fraction who passed phase I = 1-\frac{4}{9}=\frac{5}{9}

Now, it is also provided that 5/7 of those who passed the first phase were eliminated in the second phase.

Then the fraction of candidates who passed the second phase is:

Fraction who passed phase II = 1-\frac{5}{7}=\frac{2}{7}

That is, 2/7 of the remaining applicants passed the second phase.

The fraction of the applicants who have passed the two phases is:

\frac{5}{9}\times \frac{2}{7}=\frac{10}{63}

Thus, the fraction of the applicants who have passed the two phases of the selection process is \frac{10}{63}.

8 0
3 years ago
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